Page:The mystic test book.djvu/242

238 This is a solution of the problem which is indeed a tedious one by ordinary mathematics. What is more, it is absolutely correct. Avoirdupois weight is used, as that is the one for large weights.

EXAMPLE FOR PRACTICE.

How many pounds of sugar of milk would there be, to one grain of salt, in a potency of 20, of natrum muriaticum? Ans. 14,285,714,285,714,285 or over fourteen quadrillions.

RULE NUMBER II.

To find how many tons of a trituration would contain one grain of the drug. Subtract eight from the number of the potency, or P—8=x.

Begin at the 7 point and set down the figures as in rule 1 to the amount of x. This gives the answer in tons.

Example: How many tons of sugar of milk would contain a grain of the active principle, at the 32d trituration, or potency?

Ans. 714,285,714,285,714,285,714,285, or over seven hundred sextillions of tons.

The statement made by me in "Temple Lectures" was equivalent to less than 20 sextillions of tons, so that if I had said the thirty-second potency, instead of the thousandth, my statement would then have been far below the truth, or thirty-five times too small.

I do not intend to throw a straw in the way of that practice, however. In fact, I am a full believer in it and have used none other in my family for years. But I do want to impress upon the minds of our readers the great truth that the unseen astral potencies are stronger than the seen. I firmly believe that the potency of high homeopathic dilutions