Page:The Rhind Mathematical Papyrus, Volume I.pdf/103

43] times 10; it makes 790$1/undefined$$1/undefined$$1/undefined$$1/undefined$ cubed cubits. Add $1/undefined$ of it to it; it makes 1185$1/undefined$$1/undefined$, its contents in khar. $1/undefined$ of this is 59$1/undefined$$1/undefined$. 59$1/undefined$$1/undefined$ times 100 hekat of grain will go into it.

Method of working out:

Problem 43

A cylindrical granary of diameter 9 and height 6. What is the amount of grain that goes into it?

Do it thus: Take away $2/3$ of it, namely, 1, from 9; the remainder is 8. Add to 8 its $1/undefined$; it makes 10$1/undefined$. Multiply 10$2/3$ times 10$1/undefined$; it makes 113$1/undefined$$1/undefined$. Multiply 113$1/undefined$$2/3$ times 4, 4 cubits being $2/3$ of the height; it makes 455 $1/undefined$, its contents in khar. Find $1/undefined$ of this, namely, 22$1/undefined$$1/undefined$$2/3$. The amount of grain that will go into it is 22$1/undefined$$1/undefined$ times 100 hekat $1/undefined$$1/undefined$$1/undefined$ hekat 2$1/undefined$$1/undefined$$1/undefined$ ro.

Method of working out: