Page:The Rhind Mathematical Papyrus, Volume I.pdf/102

 CHAPTER II. GEOMETRY SECTION I

Problem 41

Find the volume of a cylindrical granary of diameter 9 and height 10.

Take away $1/undefined$ of 9, namely, 1; the remainder is 8. Multiply 8 times 8; it makes 64. Multiply 64 times 10; it makes 640 cubed cubits. Add $1/undefined$ of it to it; it makes 960, its contents in khar. Take $1/undefined$ of 960, namely 48. 4800 hekat of grain will go into it.

Method of working out:

Problem 42

Find the volume of a cylindrical granary of diameter 10 and height 10.

Take away $1/undefined$ of 10, namely 1$1/undefined$;the remainder is 8$1/undefined$$2/3$$1/undefined$. Multiply 8$1/undefined$$1/undefined$$2/3$ times 8$1/undefined$$1/undefined$$2/3$; it makes 79$1/undefined$$1/undefined$. Multiply 79$2/3$$1/undefined$