Page:Reflections on the Motive Power of Heat.djvu/193

Rh latent heat of a pound of saturated steam, by the equation

$$k = \frac{p}{760} \cdot \frac{ 1 + .00366 \times 100}{1 + .00366 \times t\quad} \cdot \times {.036869} \,. \lambda ,$$

where p denotes the pressure in millimetres, and λ the latent heat of a pound of saturated steam; the values of λ, being calculated by the empirical formula

$$\lambda = (606.5 + 0.305 t) - (t + .00002 t^2 + 0.0000003t^3), $$

given by Regnault as representing, between the