Page:Light waves and their uses.djvu/46

28 distances from this point, and hence will not arrive in the same phase, and the brightness will be less than at p. At a certain distance pq there will be no light at all. This occurs when the difference of phase between the extreme ray and the central ray is half a wave, that is, calling the wave length l, when cq − bq = l; for these two pairs of rays destroy each other, and the same is true of every two such pairs of rays.

The same is equally true of every point about p at this same distance; hence there will be a dark ring about the bright image. This is succeeded by a bright ring, a second dark ring, and so on.

The radius of the first dark ring may be calculated as follows:

Draw qt at right angles to bp. Then cq − bq = l. But cq = cp, very nearly, and cp = bp, and bq = bt, so that bp − bq = pt = l.

But the triangles pqt and pbc are similar, whence pt:pq = bc:bp; or, calling r the radius of the first dark ring, F the focal length of the lens, and D the diameter of the lens, r = $F⁄D$ l; that is, the radius of the dark ring is greater than the length of the light wave, in the same proportion as the focal length of the lens is greater than its diameter. For example, if the length of the light wave be taken as one fifty-thousandth of an inch, and the focal length of the lens as one hundred times the diameter, then this radius will be one five-hundredth of an inch—a quantity readily perceptible with a moderate eyepiece. The lack of distinctness of the image would be of the same order, and would be further aggravated by greater magnification, resembling a drawing made with a blunt point.