Page:LA2-NSRW-5-0172.jpg



2156

ARITHMETIC

To prove  an example  in division,  multiply the  quotient by the divisor, and add the remainder, if there is one.

EXERCISE 7. Divide and prove the following:

1. 6)568

2. 8^9655

3. 9)15432

4. 7)98746

5. 10)76482

6. . 8) 200416

7. 7)4732

8. 4^2116

9. 5)24806

10. 6)85429

11. 9)46681

12. 6)15116

13. 5)5263

14. 3J2004

15. 7)19019

16. 8)34702

17. 5)84763

18. 7)34816

19. 9)6248

20. 6)5084

21. 4)49048

22. 3)15161

23. 2)14631

24. 4)648161

LONG DIVISION.

Divide 8401 by 31.

The process of long division is the same as that of short

271  division, except that in long division we express the sueees-

31)8401   sive partial dividends.

62            We find the quotient figure by comparing the first one, or

--  the first two dividend figures with the first divisor figure.

220           In the above example:

217                 3 is contained in   8, 2 times.

-                3 is contained in 22, 7 times.

31                3 is contained in   3, once.

31         Thus the quotient is 271.

—         Always place the quotient figure directly over the dividend

0  figure that produced it.

Divide 8401 by 82.

Examples where we have zero in the quotient often give trouble.

102J-I

82)8401 82

Practice, however, does away with the difficulty. We find in the above example that 82 from 84 leaves a remainder of 2: bring down the 0. We see that 82 is not contained in 20; write 0 in the quotient directly over the dividend figure which was last brought down, and bring down the next figure 1. 82 is contained in 201 twice. Thus

--    the quotient is 102 with a remainder of 37.

37 remainder.

If after bringing down another figure the divisor is still larger than the partial dividend, write another 0 in the quotient, and bring down the next quotient figure.

201 164