Page:Journal of the American Society of Mechanical Engineers, Volume 33.pdf/680

Rh Also

where
 * $$V_s$$ = speciﬁc volume of saturated steam (volume of 1 lb.) at a given temperature, $$t$$, Pressure $$e$$
 * $$V_a$$, = speciﬁc volume of air at the same pressure and temperature
 * $$D_s$$ = density of saturated steam in lb. per cu. ft. at temperature $$t$$

But we have for air

Therefore

Hence, substituting in [34]


 * $$(P - e)$$ in. mercury = $$(144 \times 0.4908) (P - p)$$ lb. per sq. ft.

Hence