Page:International Library of Technology, Volume 93.djvu/84



therefore, require but 5.8 pounds of air, the products of combustion being as indicated below:

Mixture, in Pounds Elements, in Pounds Products, in Pounds Carbon, 1 Carbon, 1 = Carbon monoxide, 2.334 Air, 5.8 = Oxygen, 1.334 Nitrogen, 4.466 Nitrogen, 4.466 Total, 6.8 Total, 6.8 Total, 6.8

Since an additional supply of 5.8 pounds of air would be required to convert 2.334 pounds of CO into CO,, the complete combustion of 1 pound of CO would require 5.8 ÷ 2.334 = 2.48 pounds of air. The truth of this statement is verified as follows: By referring to the atomic weights of C and O, it will be seen that 1 pound of CO is composed

TABLE III Name of Gas Cubic Feet of Air Required per Cubic Foot of Gas Products of Combustion Hydrogen, H 2.38 Water Nitrogen Water Marsh gas, CH4 9.52 Carbon dioxide Nitrogen Water Sulphureted hydrogen, H2S 7.14 Sulphur dioxide Nitrogen Carbon monoxide, CO 2.38 Carbon dioxide Nitrogen

of 12 parts, by weight, of C and 16 parts, by weight, of O; consequently, to complete the combustion of 1 pound of CO, $16⁄16 + 12$ = $16⁄28$ or .57 pound of O is required. As air contains only 23 per cent, of O, the amount of air required will be .57 ÷ .23 = 2.48 pounds. Carbon monoxide, CO, is