Page:Geographical description of Scotland.pdf/16

 A Tide TABLE                        h   North. South. Queensburgh, Iſle of wight   0 00 NBE        SBW             Aberdene, Rocheſter           0 45 NEBN       SWBS            Graves-end, Downs Scilly      1 30 NE         SW              Leith, St Andrews, Dundee     2 15 NEBE       SWBW            London, Tinmouth, Amſterd. 3 00  ENE         WSW             Berwick,Flamburghhead         3 45 EBN        WBS             Kingſaile, Baltimore,Uſhant   4 30 Newcastle, humber, Lizard    5 15 Eaſt       weſt            Briſtol, Plimouth, Hull       6 00 EBS        WBN             Waterford, Abermorick         6 45 ESE        WNW             Portruth, Milnford, Texel     7 30 SEBE       NWBW            Dublin, lamby, the Hague      8 15 SE         NW              Dumbar, Iſle of Man, Orkney   9 00 SEBS       NWBN            North and ſouth Foreland      9  4 SSE        NNW             Yarmouth, Dover, Harwich     10 30 SBE        NBW             Rye, Winchelſy, Culſhot      11 15 The Uſe.

Having known what Moon makes full Sea in any Port or Harbour, ( as you have a Table here of the moſt re-  markable ) you muſt multiply the Moons age by 4,and di- vide the product by 5, the quotient will be hours, and the remainders will be 5 parts of an hour, ( every 5 part  being 12') for the time of the Moons ſouthing, and ad- ding 24 thereto will be her northing; very near to which add the hours and minuts belonging to the point of flow- ing, and then ſeek the Moons age in this Table, under

Moons age        h,  '      the moons age and to- 1 : 14 : 16 : 29    0 :  0     wards the right hand 2 : 13 : 17 : 28    0 :  5     you have the hours and 3 : 12 : 18 : 27    0 : 10     minuts to be ſubtracted 4 : 11 : 19 : 26    0 : 20     from the former ſum, so      5 : 10 : 20 : 25     0 : 30     the remainder is true 6 : 9 : 21 : 24     0 : 45     time of full sea. 7 : 8 : 22 : 23     1 : 00              Example. I demand full sea Leith the 6 day of the Moons age? Anſwer, multiply 6 by    4, product is 24, which divide by 5, quotient is 4 and 4/5 48' to which ad 2 h 15' belonging to NEBN or SWE for Leith, ſum is 5 h. from which ſubtract 45' found in the laſt Table, remainder is 4 h, 18' true time of full sea, Leith required. F I N I S.