Page:Foster's Russian bank; a card game for two players (second edition).djvu/94

78 so as to make one more card for him to pay for. This is better than playing it into the tableau, when it is not wanted there. The last card of all, the ♢8, goes into the vacant space and wins the game, leaving the non-dealer with three cards to pay for.

This goes to show that in the actual play the dealer got rid of sixteen cards and was paid for the game and three, when his opponent should have won the game, and forced the dealer to pay for those sixteen cards into the bargain.

If the reader will go back to the point at which the non-dealer blocked the spade suit, and will play the hand in accordance with the situation revealed by a careful study of the extended discards, some instructive points will be brought out, and the manner in which the opponent’s