Page:Euclid's Elements 1714 Barrow translation.djvu/22

10 of DE, decribe the circle DEH; and let DA e be produced to the point G in the circumference thereof. Then AG = CB.

For DG f = DE, and DA g = DC. Wherefore AG b = CE k = BC l = AG. Which was to be done.

The putting of the point A within or without the line BC varies the caes; but the contruction, and the demontration, are every where alike.

The line AG might be taken with a pair of compaes; but the o doing anwers to no Potulate, as Proclus well intimates.

Two right lines, A and BC, being given, from the greater BC to take away the right line BE equal to the leer A.

At the point B a draw the right line BD = A. The circle decribed from the center B at the ditance of BD hall cut off BE b = BD c = A d = BE. Which was to be done.

If two triangles BAC, EDF, have two ides of the one BA, AC equal to two ides of the other ED, DF, each to its correpondent ide (that is, BA = ED,