Page:Description and Use of a New Celestial Planisphere.pdf/45

40 if 24h give 42', what will 6h 30m give?—Answer, 11' 20": ubtract this from 7s 23° 49', the Longitude at noon on the second day, and the remainder is, 7s 23° 37' 40", the true Longitude of Mercury at the time required; then for the Latitude of the Planet, oberve, on the firt day it is 2° 16' South; and on the eventh day, 0° 38' South, and of coure decreaing: ubtract, and the difference is 1° 38': then say, if ix days give 1° 38', what will 1 day, 6h 30m give?—Answer, 20' 21', to be ubtracted from the Latitude on the firt day, 2° 16', and it leaves 1° 55' 39" for the true South Latitude of the Planet at the day and hour propoed; eek thee points in Longitude and Latitude in the Zodiac of the Planisphere, and that is the true and corrected place of Mercury for the time required, viz. in 7s 23° 37' 40", and between the Stars in the Scales, and the Claws of the Scorpion, and you may take the right Acenion and Declination of the Planet at the time, as before taught; by this rule, we have the ituation of all the Planets among the Stars at any time required, and by which, any peron may learn to ditinguih, and know them by ight from the fixed Stars, and to trace their progreive motions continually.

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