Page:Conversations, between James Block, Esq. and Millar, the editor of the Monthly Miscellany.pdf/16

16 Duplicate Geometrical Progression of the National Debt in of pounds each term being seventeen and a half years.

3

8

1698

4

16

1715 $1⁄2$

6

64

1750 $1⁄2$

7

128

1768

8

256

1785 $1⁄2$

9

512

1803

18

It appears from this statement, that the National Debt had led itself since its commencement, 120 years ago, in abootabout [sic] seventeen and a half years, upon an average. Allow the debt in 1820, to be 1024 millions of poondspounds [sic], and to  that ratio, what will be the amount of the national chebt in 30

Solution. 1024 millions squared=1048576= years additional, or till anno 1995. 1048576 squared=1,099,511,627,776 millions=350 years  or 2345  1,099,511,627,776 millions =1,208,925,819,614,629,174,706,176 700 years additional; or anno 3045. Or, 1 septillion, thousand, 925 quadrillion, 819 thousand, 614  629 thousand, 174 billion, 706 thousand 176

XVII. The diameter of the earth, from the latest is 42073016 feet, A cubic foot of fine gold is 1506.135168 lbs. weight, and a pound Troy weight of fine gold is equal in 48 pound sterling. Required how many globe of fine solid and each of them as large as the globe of our earth, will the  of the National Debt be equal to, on anno 3045, according to  geometicalgeometrical [sic] progression mentioned in last question?

Solution. The answer of the last question divide £48 gives 25185951575304774473045333333 $1⁄3$  troy of fine gold. Then the cube of 42073016 is 74501628045372347908096 feet, cube of the  of the earth; then this last number multiplied  .5236, being the 6th part of 3.1416 (the  of a circle whose diameter is one) and the product  be equal to 39009052444556961364679.0656, the  feet in the globe of the earth. Then this last duct being multiplied into 1506.135168 lbs. 58752905757103609690560413.73354 lbs. Troy gold: equal to the globe of our earth. Ans 428 $1⁄2$ gl of fine solid gold each of them as large as the of our earth. Interest at 2 $1⁄2$ per cent=10 $1⁄2$ of fine gold, and each of of them as large as our

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