Page:Carroll (1884).djvu/31

 In case (c), the x Electors can, as in case (a), supply s Candidates with $vx⁄x$ votes apiece. But each of the (e − x) Electors can only use (m + 1 − s) of his votes: hence the (e − x) Electors can only give (m + 1 − s).(e − x) votes, thus supplying (m + 1 − s) Candidates with (e − x) votes apiece. Hence we must have

In case (d), the x Electors can, as in case (b), supply s Candidates with x votes apiece. And the (e − x) Electors can, as in case (c), supply (m + 1 − s) Candidates with (e − x) votes apiece. Hence we must have