Page:Calculus Made Easy.pdf/169

 This gives

hence, reverting to the original function, we get

Next try

First change to natural logarithms by multiplying by the modulus $$0.4343.$$ This gives us

whence

The next thing is not quite so simple. Try this:

Taking the logarithm of both sides, we get

Since $$\dfrac{1}{\log_\epsilon a}$$ is a constant, we get

hence, reverting to the original function.